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The Coleman family is moving to a new home on the other side of the state. Lucy Coleman leaves first, hauling a trailer and traveling at a constant speed of 5555 miles per hour. When her husband, Tristan, leaves in his car, Lucy is already 1010 miles away. Tristan drives at a constant speed of 6060 miles per hour.\newlineWhich equation can you use to find hh, the number of hours it will take for Tristan to catch up to Lucy?\newlineChoices:\newline(A) 10+55h=60h10 + 55h = 60h\newline(B) 55+10h=60h55 + 10h = 60h\newlineHow long will it take for Tristan to catch up to Lucy?\newlineSimplify any fractions.\newline____ hours

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Q. The Coleman family is moving to a new home on the other side of the state. Lucy Coleman leaves first, hauling a trailer and traveling at a constant speed of 5555 miles per hour. When her husband, Tristan, leaves in his car, Lucy is already 1010 miles away. Tristan drives at a constant speed of 6060 miles per hour.\newlineWhich equation can you use to find hh, the number of hours it will take for Tristan to catch up to Lucy?\newlineChoices:\newline(A) 10+55h=60h10 + 55h = 60h\newline(B) 55+10h=60h55 + 10h = 60h\newlineHow long will it take for Tristan to catch up to Lucy?\newlineSimplify any fractions.\newline____ hours
  1. Set Up Equation: Let's first set up the equation to find hh, the number of hours it will take for Tristan to catch up to Lucy. We know that Lucy has a 1010-mile head start and is traveling at 5555 miles per hour. Tristan is traveling at 6060 miles per hour. We want to find the point where the distance Tristan has traveled equals the distance Lucy has traveled plus her 1010-mile head start.\newlineThe distance that Lucy travels can be represented as 55h55h (since distance = speed ×\times time), and the distance that Tristan travels can be represented as 60h60h. To account for Lucy's head start, we add 1010 miles to her distance. Therefore, the equation that represents the situation is:\newline10+55h=60h10 + 55h = 60h\newlineThis is choice (A).
  2. Find h: Now we need to solve the equation for hh.\newline10+55h=60h10 + 55h = 60h\newlineSubtract 55h55h from both sides to isolate the variable hh on one side of the equation:\newline10+55h55h=60h55h10 + 55h - 55h = 60h - 55h\newline10=5h10 = 5h\newlineNow, divide both sides by 55 to solve for hh:\newline105=5h5\frac{10}{5} = \frac{5h}{5}\newline2=h2 = h\newlineSo, it will take Tristan 10+55h=60h10 + 55h = 60h00 hours to catch up to Lucy.

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