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The bacteria in a Petri dish culture are self-duplicating at a rapid pace.
The relationship between the elapsed time 
t, in minutes, and the number of bacteria, 
B(t), in the Petri dish is modeled by the following function.

B(t)=10*2^((t)/( 12))
How many bacteria will make up the culture after 120 minutes?
Round your answer, if necessary, to the nearest hundredth.
bacteria

The bacteria in a Petri dish culture are self-duplicating at a rapid pace.\newlineThe relationship between the elapsed time t t , in minutes, and the number of bacteria, B(t) B(t) , in the Petri dish is modeled by the following function.\newlineB(t)=102t12 B(t)=10 \cdot 2^{\frac{t}{12}} \newlineHow many bacteria will make up the culture after 120120 minutes?\newlineRound your answer, if necessary, to the nearest hundredth.\newlinebacteria

Full solution

Q. The bacteria in a Petri dish culture are self-duplicating at a rapid pace.\newlineThe relationship between the elapsed time t t , in minutes, and the number of bacteria, B(t) B(t) , in the Petri dish is modeled by the following function.\newlineB(t)=102t12 B(t)=10 \cdot 2^{\frac{t}{12}} \newlineHow many bacteria will make up the culture after 120120 minutes?\newlineRound your answer, if necessary, to the nearest hundredth.\newlinebacteria
  1. Identify function: Identify the given function that models the number of bacteria over time.\newlineThe function is B(t)=102t12B(t) = 10 \cdot 2^{\frac{t}{12}}.
  2. Substitute time: Substitute the given time t=120 t = 120 minutes into the function to find B(120) B(120) .B(120)=10×2(120/12) B(120) = 10 \times 2^{(120/12)} .
  3. Simplify exponent: Simplify the exponent by dividing 120120 by 1212.\newline12012=10\frac{120}{12} = 10.
  4. Calculate power: Calculate 22 raised to the power of 1010.\newline210=10242^{10} = 1024.
  5. Multiply result: Multiply the result from Step 44 by 1010 to find the number of bacteria after 120120 minutes.\newlineB(120)=10×1024B(120) = 10 \times 1024.
  6. Perform multiplication: Perform the multiplication to get the final result. B(120)=10×1024=10240B(120) = 10 \times 1024 = 10240.

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