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Avery is designing a large rectangular sign. They want the sign to have an area of 
2m^(2) and a width of 
(4)/(5)m.
How tall should the sign be?
m

Avery is designing a large rectangular sign. They want the sign to have an area of 2 m2 2 \mathrm{~m}^{2} and a width of 45 m \frac{4}{5} \mathrm{~m} .\newlineHow tall should the sign be?\newlinem

Full solution

Q. Avery is designing a large rectangular sign. They want the sign to have an area of 2 m2 2 \mathrm{~m}^{2} and a width of 45 m \frac{4}{5} \mathrm{~m} .\newlineHow tall should the sign be?\newlinem
  1. Area Formula: To find the height of the sign, we need to use the formula for the area of a rectangle, which is Area=Width×Height\text{Area} = \text{Width} \times \text{Height}. We know the Area\text{Area} and the Width\text{Width}, so we can solve for the Height\text{Height}.
  2. Given Values: The area of the sign is given as 22 square meters (2m22\,\text{m}^2), and the width is given as 45\frac{4}{5} meters (45m\frac{4}{5}\,\text{m}). Let's denote the height as HH meters (HmH\,\text{m}).
  3. Area Calculation: Using the area formula, we have:\newlineArea = Width ×\times Height\newline2m2=(45)m×Hm2m^2 = \left(\frac{4}{5}\right)m \times Hm
  4. Height Calculation: To find the height ( extit{H}), we need to divide the area by the width:\newline extit{H} = extit{Area} / extit{Width}\newline extit{H} = 2m22m^2 / (4/5)m(4/5)m
  5. Division and Multiplication: Now we perform the division:\newlineH=2m2(45)mH = \frac{2m^2}{\left(\frac{4}{5}\right)m}\newlineTo divide by a fraction, we multiply by its reciprocal:\newlineH=2m2×(54)H = 2m^2 \times \left(\frac{5}{4}\right)
  6. Final Height: Multiplying the two values gives us the height:\newlineH = (2×5)/4(2 \times 5) / 4\newlineH = 10/410 / 4\newlineH = 2.52.5m

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