The area of a rectangular ink pad is 48square centimeters. The perimeter is 28centimeters. What are the dimensions of the ink pad?____ centimeters by ____ centimeters
Q. The area of a rectangular ink pad is 48square centimeters. The perimeter is 28centimeters. What are the dimensions of the ink pad?____ centimeters by ____ centimeters
Define Variables: Let l be the length and w be the width of the rectangular ink pad.The area of a rectangle is given by the formula A=l×w.
Area and Perimeter Formulas: The area of the ink pad is given as 48 square centimeters.Substitute 48 for A in the area formula.48=l×w
Equations Setup: The perimeter of a rectangle is given by the formula P=2l+2w.The perimeter of the ink pad is given as 28 centimeters.Substitute 28 for P in the perimeter formula.28=2l+2w
Solve Simultaneously: Divide the perimeter equation by 2 to simplify.228=2(2l+2w)14=l+w
Rearrange Perimeter Equation: We now have two equations with two variables:48=l×w (Area equation)14=l+w (Perimeter equation)We can solve these equations simultaneously to find the values of l and w.
Substitute and Expand: Rearrange the perimeter equation to express one variable in terms of the other. w=14−l
Quadratic Equation: Substitute w=14−l into the area equation.48=l×(14−l)
Factorize: Expand the equation and form a quadratic equation.48=14l−l2Move all terms to one side to set the equation to zero.l2−14l+48=0
Solve for Length: Factor the quadratic equation.(l−6)(l−8)=0
Final Solutions: Solve for l by setting each factor equal to zero.l−6=0 or l−8=0l=6 or l=8
Final Solutions: Solve for l by setting each factor equal to zero.l−6=0 or l−8=0l=6 or l=8If l=6, then w=14−l=14−6=8.If l=8, then w=14−l=14−8=6.Both pairs (6,8) and l−6=00 are valid solutions since a rectangle can have its length and width interchanged.
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