Q. The area of a rectangular garage is 30square meters. The perimeter is 22meters. What are the dimensions of the garage?____ meters by ____ meters
Define Variables: Let l be the length and w be the width of the rectangular garage.The area of a rectangle is given by the formula A=l×w.
Area and Perimeter Formulas: The area of the garage is given as 30 square meters.Substitute 30 for A in the formula A=l×w.30=l×w
Substitute Values: The perimeter of a rectangle is given by the formula P=2l+2w. The perimeter of the garage is given as 22 meters. Substitute 22 for P in the formula P=2l+2w. 22=2l+2w
Simplify Perimeter Equation: Divide the perimeter equation by 2 to simplify.222=22l+2w11=l+w
Solve System of Equations: We now have two equations with two variables:30=l×w (Area equation)11=l+w (Perimeter equation)We can solve this system of equations to find the values of l and w.
Express Width in Terms of Length: From the perimeter equation, express w in terms of l.w=11−l
Substitute Width into Area Equation: Substitute w=11−l into the area equation.30=l×(11−l)
Distribute and Rearrange Equation: Distribute l across the parentheses. 30=11l−l2
Factor Quadratic Equation: Rearrange the equation into a standard quadratic form.0=l2−11l+30
Solve for Length: Factor the quadratic equation.(l−5)(l−6)=0
Find Width: Solve for l by setting each factor equal to zero.l−5=0 or l−6=0l=5 or l=6
Final Valid Solutions: If l=5, then w=11−l=11−5=6. If l=6, then w=11−l=11−6=5. Both pairs (5,6) and (6,5) are valid solutions since a rectangle can have its length and width interchanged.
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