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The area of a rectangular cutting board is 8080 square inches. The perimeter is 3636 inches. What are the dimensions of the cutting board?\newline___\_\_\_ inches by ___\_\_\_ inches

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Q. The area of a rectangular cutting board is 8080 square inches. The perimeter is 3636 inches. What are the dimensions of the cutting board?\newline___\_\_\_ inches by ___\_\_\_ inches
  1. Define Variables: Let ll be the length and ww be the width of the rectangular cutting board.\newlineThe area of a rectangle is given by the formula A=l×wA = l \times w.
  2. Area and Perimeter Formulas: The area of the cutting board is given as 8080 square inches.\newlineSubstitute 8080 for AA in the formula A=l×wA = l \times w.\newline80=l×w80 = l \times w
  3. Substitute Values: The perimeter of a rectangle is given by the formula P=2l+2wP = 2l + 2w.\newlineThe perimeter of the cutting board is given as 3636 inches.\newlineSubstitute 3636 for PP in the formula P=2l+2wP = 2l + 2w.\newline36=2l+2w36 = 2l + 2w
  4. Simplify Perimeter Equation: Divide the perimeter equation by 22 to simplify.\newline362=2l+2w2\frac{36}{2} = \frac{2l + 2w}{2}\newline18=l+w18 = l + w
  5. Solve System of Equations: We now have two equations with two variables:\newline80=l×w80 = l \times w (Area equation)\newline18=l+w18 = l + w (Perimeter equation)\newlineWe can solve this system of equations to find the values of ll and ww.
  6. Express Width in Terms of Length: Rearrange the perimeter equation to express ww in terms of ll.w=18lw = 18 - l
  7. Substitute into Area Equation: Substitute w=18lw = 18 - l into the area equation 80=l×w80 = l \times w.\newline80=l×(18l)80 = l \times (18 - l)
  8. Form Quadratic Equation: Expand the equation and move all terms to one side to form a quadratic equation.\newline80=18ll280 = 18l - l^2\newline0=l218l+800 = l^2 - 18l + 80
  9. Factor Quadratic Equation: Factor the quadratic equation.\newline0=(l10)(l8)0 = (l - 10)(l - 8)
  10. Solve for Length: Solve for ll by setting each factor equal to zero.l10=0l - 10 = 0 or l8=0l - 8 = 0l=10l = 10 or l=8l = 8
  11. Find Valid Solutions: If l=10l = 10, then w=18l=1810=8w = 18 - l = 18 - 10 = 8. If l=8l = 8, then w=18l=188=10w = 18 - l = 18 - 8 = 10. Both pairs (10,8)(10, 8) and (8,10)(8, 10) are valid solutions since a rectangle can have its length and width interchanged.

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