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sum_(y=1)^(2)(1-y)=

y=12(1y)= \sum_{y=1}^{2}(1-y)=

Full solution

Q. y=12(1y)= \sum_{y=1}^{2}(1-y)=
  1. Define Series: The series is a finite series with two terms, corresponding to y=1y=1 and y=2y=2. We will evaluate the expression (1y)(1-y) for each value of yy and then sum the results.
  2. Evaluate y=1y=1: First, we substitute y=1y=1 into the expression (1y)(1-y) to get the first term of the series. This gives us 11=01 - 1 = 0.
  3. Evaluate y=2y=2: Next, we substitute y=2y=2 into the expression (1y)(1-y) to get the second term of the series. This gives us 12=11 - 2 = -1.
  4. Sum Terms: Now, we add the two terms of the series together. The sum is 0+(1)=10 + (-1) = -1.

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