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sum_(x=1)^(3)(4x)=

x=13(4x)= \sum_{x=1}^{3}(4 x)=

Full solution

Q. x=13(4x)= \sum_{x=1}^{3}(4 x)=
  1. Define Arithmetic Series: We are asked to find the sum of the expression 4x4x as xx takes on each integer value from 11 to 33. This is a finite arithmetic series where we can simply plug in the values of xx and add the results.
  2. Substitute x values: First, we substitute x=1x = 1 into the expression 4x4x.4×1=44 \times 1 = 4
  3. Calculate results: Next, we substitute x=2x = 2 into the expression 4x4x.4×2=84 \times 2 = 8
  4. Add results: Finally, we substitute x=3x = 3 into the expression 4x4x.4×3=124 \times 3 = 12
  5. Add results: Finally, we substitute x=3x = 3 into the expression 4x4x.4×3=124 \times 3 = 12Now, we add the results of the expression for each value of xx.Sum=4+8+12\text{Sum} = 4 + 8 + 12Sum=24\text{Sum} = 24

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