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sum_(x=1)^(2)(6x)=

x=12(6x)= \sum_{x=1}^{2}(6 x)=

Full solution

Q. x=12(6x)= \sum_{x=1}^{2}(6 x)=
  1. Given Expression: The given expression is a finite arithmetic series where we sum the values of 6x6x for each integer xx from 11 to 22.
  2. Calculate Term for x=1x = 1: First, we calculate the term for x=1x = 1, which is 6×1=66 \times 1 = 6.
  3. Calculate Term for x=2x = 2: Next, we calculate the term for x=2x = 2, which is 6×2=126 \times 2 = 12.
  4. Find Total Sum: Now, we add the two terms together to find the total sum: 6+12=186 + 12 = 18.

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