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sum_(n=1)^(3)(n-1)=

n=13(n1)= \sum_{n=1}^{3}(n-1)=

Full solution

Q. n=13(n1)= \sum_{n=1}^{3}(n-1)=
  1. Arithmetic series definition: The series is a simple arithmetic series where each term is given by n1n-1. We will calculate each term separately and then add them together.
  2. Calculating the first term: First term: Substitute n=1n=1 into (n1)(n-1) to get (11)(1-1) which equals 00.
  3. Calculating the second term: Second term: Substitute n=2n=2 into (n1)(n-1) to get (21)(2-1) which equals 11.
  4. Calculating the third term: Third term: Substitute n=3n=3 into (n1)(n-1) to get (31)(3-1) which equals 22.
  5. Adding all the terms: Now, we add all the terms together: 0+1+20 + 1 + 2.
  6. Sum of the series: The sum of the series is 0+1+2=30 + 1 + 2 = 3.

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