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sum_(k=0)^(1)(2-k)=

$\sum_{k=0}^{1}(2-k)=$

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Find derivatives using the chain rule I

Full solution

Q.

\sum_{k=0}^{1}(2-k)=

Series Calculation: The series is finite and only has two terms, for $k=0$ and $k=1$ . We will calculate each term separately.
Term for $k=0$ : For $k=0$ , the term is $(2-0)$ , which equals $2$ .
Term for $k=1$ : For $k=1$ , the term is $(2-1)$ , which equals $1$ .
Sum of Terms: Now, we add the two terms together: $2 + 1 = 3$ .

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