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sum_(k=0)^(1)(2-k)=

∑k=01(2−k)= \sum_{k=0}^{1}(2-k)=

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Full solution

Q. ∑k=01(2−k)= \sum_{k=0}^{1}(2-k)=
  1. Series Calculation: The series is finite and only has two terms, for k=0k=0 and k=1k=1. We will calculate each term separately.
  2. Term for k=0k=0: For k=0k=0, the term is (2−0)(2-0), which equals 22.
  3. Term for k=1k=1: For k=1k=1, the term is (2−1)(2-1), which equals 11.
  4. Sum of Terms: Now, we add the two terms together: 2+1=32 + 1 = 3.

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