Q. Subtract.The numerator should be expanded and simplified. The denominator should be either expanded or factored.2x2+18x7−x2+17x+725x=
Identify common denominator: Identify the common denominator for the two fractions.The denominators are 2x2+18x and x2+17x+72. To combine the fractions, we need a common denominator. The common denominator will be the least common multiple (LCM) of the two denominators.
Factor denominators: Factor the denominators if possible.The first denominator, 2x2+18x, can be factored by taking out the common factor of 2x, which gives us 2x(x+9).The second denominator, x2+17x+72, can be factored into (x+8)(x+9).
Determine LCM of factored denominators: Determine the LCM of the two factored denominators.The LCM of 2x(x+9) and (x+8)(x+9) is 2x(x+8)(x+9), since (x+9) is common in both and we need to include all other distinct factors.
Rewrite fractions with common denominator: Rewrite each fraction with the common denominator.The first fraction becomes (2x(x+9)7) and the second fraction becomes ((x+8)(x+9)5x). To have the same denominator, we multiply the numerator and denominator of the first fraction by (x+8) and the numerator and denominator of the second fraction by 2x.
Multiply numerators by appropriate factors: Multiply the numerators by the appropriate factors.For the first fraction, we have (7×(x+8))/(2x(x+8)(x+9)).For the second fraction, we have (5x×2x)/(2x(x+8)(x+9)).
Expand numerators: Expand the numerators.For the first fraction, we have (7x+56)/(2x(x+8)(x+9)).For the second fraction, we have (10x2)/(2x(x+8)(x+9)).
Subtract second fraction from first fraction: Subtract the second fraction from the first fraction.Now we have 2x(x+8)(x+9)(7x+56)−(10x2).
Combine numerators: Combine the numerators.We get (7x+56−10x2)/(2x(x+8)(x+9)).
Simplify numerator: Simplify the numerator.We have (−10x2+7x+56)/(2x(x+8)(x+9)).
Check for possible simplification or factoring: Check for any possible simplification or factoring. The numerator is a quadratic expression and does not factor further in relation to the denominator. Therefore, this is the final simplified form of the expression.