Subtract. (3)/(10)-(9)/(10)=

Identify common denominator: Identify the common denominator. Both fractions have the same denominator, which is 10. This means we can subtract the numerators directly.Subtract numerators: Subtract the numerators. Subtract the numerator of the second fraction from the numerator of the first fraction: 3 - 9. 3 - 9 = -6Write over common denominator: Write the result over the common denominator. Since the common denominator is 10, the result of the subtraction is -6/10.Simplify fraction: Simplify the fraction, if possible. The fraction -6/10 can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2. -6/10 ÷ 2/2 = -3/5

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Subtract. $\newline$ $\frac{3}{10}-\frac{9}{10}=$

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Math Problems

Grade 7

Powers with negative bases

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Q. Subtract.

\newline

\frac{3}{10}-\frac{9}{10}=

Identify common denominator: Identify the common denominator. $\newline$ Both fractions have the same denominator, which is $10$ . This means we can subtract the numerators directly.
Subtract numerators: Subtract the numerators. $\newline$ Subtract the numerator of the second fraction from the numerator of the first fraction: $3 - 9$ . $\newline$ $3 - 9 = -6$
Write over common denominator: Write the result over the common denominator. $\newline$ Since the common denominator is $10$ , the result of the subtraction is $-\frac{6}{10}$ .
Simplify fraction: Simplify the fraction, if possible. $\newline$ The fraction $-\frac{6}{10}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is $2$ . $\newline$ $-\frac{6}{10} \div \frac{2}{2} = -\frac{3}{5}$