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State all integer values of 
x in the interval 
-8 <= x <= -3 that satisfy the following inequality:

2x+10 < -4
Answer: 
x=

State all integer values of x x in the interval 8x3 -8 \leq x \leq-3 that satisfy the following inequality:\newline 2 x+10<-4 \newlineAnswer: x= x=

Full solution

Q. State all integer values of x x in the interval 8x3 -8 \leq x \leq-3 that satisfy the following inequality:\newline2x+10<4 2 x+10<-4 \newlineAnswer: x= x=
  1. Identify Inequality & Interval: Identify the inequality and the given interval.\newlineThe inequality to solve is 2x + 10 < -4, and we are looking for integer solutions within the interval 8x3-8 \leq x \leq -3.
  2. Isolate Variable xx: Isolate the variable xx on one side of the inequality.\newlineSubtract 1010 from both sides of the inequality to get 2x < -14.\newlineCalculation: 2x + 10 - 10 < -4 - 10\newline2x < -14
  3. Divide by 22: Divide both sides of the inequality by 22 to solve for xx.\newlineCalculation: \frac{2x}{2} < \frac{-14}{2}\newlinex < -7
  4. Determine Integer Values: Determine the integer values of xx that are less than 7-7 and within the given interval 8x3-8 \leq x \leq -3. Since xx must be less than 7-7, the only integer value of xx within the interval that satisfies this condition is x=8x = -8.

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