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Let’s check out your problem:
3
x
−
5
=
7
\sqrt{3x-5}=7
3
x
−
5
=
7
.Solve for `x`
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Math Problems
Grade 8
Power of a power: integer bases
Full solution
Q.
3
x
−
5
=
7
\sqrt{3x-5}=7
3
x
−
5
=
7
.Solve for `x`
Square both sides:
Square both sides of the equation to eliminate the
square root
.
(
3
x
−
5
)
2
=
7
2
(\sqrt{3x-5})^2 = 7^2
(
3
x
−
5
)
2
=
7
2
Simplify both sides:
Simplify both sides of the equation.
3
x
−
5
=
49
3x - 5 = 49
3
x
−
5
=
49
Add
5
5
5
to isolate:
Add
5
5
5
to both sides of the equation to isolate the term with
x
x
x
.
\newline
3
x
−
5
+
5
=
49
+
5
3x - 5 + 5 = 49 + 5
3
x
−
5
+
5
=
49
+
5
Combine like terms:
Simplify the equation by combining like terms.
3
x
=
54
3x = 54
3
x
=
54
Divide by
3
3
3
:
Divide both sides of the equation by
3
3
3
to solve for
x
x
x
.
3
x
3
=
54
3
\frac{3x}{3} = \frac{54}{3}
3
3
x
=
3
54
Find
x
x
x
:
Simplify the equation to find the value of
x
x
x
.
x
=
18
x = 18
x
=
18
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Question
Select the equivalent expression.
\newline
(
(
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
((8^{-5})/(2^{-2}))^{-4}=?
((
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
\newline
(
8
20
)
/
(
2
8
)
(8^{20})/(2^{8})
(
8
20
)
/
(
2
8
)
\newline
(B)
\newline
(
2
6
)
/
(
8
9
)
(2^{6})/(8^{9})
(
2
6
)
/
(
8
9
)
\newline
(C)
\newline
(
1
)
/
(
8
⋅
2
2
)
(1)/(8\cdot 2^{2})
(
1
)
/
(
8
⋅
2
2
)
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Posted 11 months ago
Question
Select the equivalent expression.
\newline
(
b
7
4
5
)
−
3
=
?
\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?
(
4
5
b
7
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
b
21
4
15
\frac{b^{21}}{4^{15}}
4
15
b
21
\newline
(B)
4
15
b
21
\frac{4^{15}}{b^{21}}
b
21
4
15
\newline
(C)
b
−
21
⋅
4
−
15
b^{-21}\cdot 4^{-15}
b
−
21
⋅
4
−
15
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Posted 1 year ago
Question
Select the equivalent expression.
\newline
(
3
3
⋅
6
6
)
−
3
=
(3^{3}\cdot6^{6})^{-3}=
(
3
3
⋅
6
6
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
1
3
9
⋅
6
18
\frac{1}{3^{9}\cdot6^{18}}
3
9
⋅
6
18
1
\newline
(B)
6
18
3
9
\frac{6^{18}}{3^{9}}
3
9
6
18
\newline
(C)
3
9
6
18
\frac{3^{9}}{6^{18}}
6
18
3
9
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Posted 1 year ago
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