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solve this equation: 9x+1+1=10(3x)9^x+1 + 1 = 10(3^x)

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Q. solve this equation: 9x+1+1=10(3x)9^x+1 + 1 = 10(3^x)
  1. Understand and Identify Bases: Understand the equation and identify similar bases.\newlineThe equation is 9x+1+1=10(3x)9^x+1 + 1 = 10(3^x). We notice that 99 is a power of 33, specifically 9=329 = 3^2. This will allow us to rewrite the equation with a common base.
  2. Rewrite and Simplify Equation: Rewrite 99 as 323^2 and simplify the equation.\newline9x+19^x+1 can be written as (32)(x+1)(3^2)^{(x+1)}. Using the power of a power rule, we get 32(x+1)3^{2(x+1)}. The equation now looks like this:\newline32(x+1)+1=10(3x)3^{2(x+1)} + 1 = 10(3^x)
  3. Expand Exponent: Expand the exponent in the term 32(x+1)3^{2(x+1)}.\newline2(x+1)2(x+1) is equal to 2x+22x + 2. So, we rewrite the equation as:\newline32x+2+1=10(3x)3^{2x+2} + 1 = 10(3^x)
  4. Divide and Simplify: Divide both sides of the equation by 3x3^x to simplify.\newline(32x+2)/(3x)+1/(3x)=10(3^{2x+2})/(3^x) + 1/(3^x) = 10\newlineUsing the quotient of powers rule, we get:\newline32x+2x+1/(3x)=103^{2x+2-x} + 1/(3^x) = 10\newlineThis simplifies to:\newline3x+2+1/(3x)=103^{x+2} + 1/(3^x) = 10
  5. Recognize Limitations: Recognize that the equation cannot be simplified further algebraically. At this point, we realize that the equation 3(x+2)+13x=103^{(x+2)} + \frac{1}{3^x} = 10 does not lend itself to further algebraic manipulation. We need to use another method, such as trial and error, graphing, or a numerical method to find the value of xx.
  6. Trial and Error Solution: Use trial and error or a numerical method to find the value of xx. Since the problem does not specify a method, we will use trial and error. We know that 30=13^0 = 1, so let's try x=0x = 0: 3(0+2)+130=32+1=9+1=103^{(0+2)} + \frac{1}{3^0} = 3^2 + 1 = 9 + 1 = 10 10=1010 = 10 This is true, so x=0x = 0 is a solution.

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