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Solve the system by substitution.

{:[y=-5x],[y=-x+4]:}

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Solve the system by substitution.\newliney=5xy=x+4 \begin{array}{l} y=-5 x \\ y=-x+4 \end{array} \newline(,) (\square, \square)

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Q. Solve the system by substitution.\newliney=5xy=x+4 \begin{array}{l} y=-5 x \\ y=-x+4 \end{array} \newline(,) (\square, \square)
  1. Set Equations Equal: Set the two equations equal to each other since they both equal yy.\newlineSince y=5xy = -5x and y=x+4y = -x + 4, we can set 5x-5x equal to x+4-x + 4.
  2. Solve for x: Solve for x.\newline5x=x+4-5x = -x + 4\newlineNow, add 5x5x to both sides to get all x terms on one side.\newline5x+5x=x+4+5x-5x + 5x = -x + 4 + 5x\newline0=4x+40 = 4x + 4
  3. Isolate xx: Isolate xx.\newlineSubtract 44 from both sides to solve for xx.\newline04=4x+440 - 4 = 4x + 4 - 4\newline4=4x-4 = 4x
  4. Divide to Find x: Divide both sides by 44 to find the value of xx.44=4x4-\frac{4}{4} = \frac{4x}{4}1=x-1 = x
  5. Substitute for y: Substitute xx back into one of the original equations to solve for yy. We can use y=5xy = -5x. y=5(1)y = -5(-1) y=5y = 5
  6. Check Solution: Check the solution with the other equation.\newlineSubstitute x=1x = -1 into y=x+4y = -x + 4.\newliney=(1)+4y = -(-1) + 4\newliney=1+4y = 1 + 4\newliney=5y = 5\newlineSince this matches the yy value we found when we substituted into the first equation, our solution is correct.

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