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Solve the system by substitution.

{:[2x+7y=48],[x=6y+5]:}

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Solve the system by substitution.\newline2x+7yamp;=48xamp;=6y+5 \begin{aligned} 2 x+7 y & =48 \\ x & =6 y+5 \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newline2x+7y=48x=6y+5 \begin{aligned} 2 x+7 y & =48 \\ x & =6 y+5 \end{aligned} \newline(,) (\square, \square)
  1. Substitute xx in first equation: Substitute the value of xx from the second equation into the first equation.\newlineWe have x=6y+5x = 6y + 5. We will substitute this into the first equation 2x+7y=482x + 7y = 48.
  2. Replace xx in equation: Replace xx in the first equation with the expression from the second equation.\newline2(6y+5)+7y=482(6y + 5) + 7y = 48
  3. Distribute and combine terms: Distribute 22 to the terms inside the parentheses.\newline12y+10+7y=4812y + 10 + 7y = 48
  4. Isolate y term: Combine like terms.\newline19y+10=4819y + 10 = 48
  5. Solve for yy: Subtract 1010 from both sides of the equation to isolate the term with yy.19y=3819y = 38
  6. Substitute yy back for xx: Divide both sides by 1919 to solve for yy.\newliney=3819y = \frac{38}{19}\newliney=2y = 2
  7. Calculate x value: Substitute the value of yy back into the second equation to solve for xx.\newlinex=6y+5x = 6y + 5\newlinex=6(2)+5x = 6(2) + 5
  8. Calculate xx value: Substitute the value of yy back into the second equation to solve for xx.
    x=6y+5x = 6y + 5
    x=6(2)+5x = 6(2) + 5 Calculate the value of xx.
    x=12+5x = 12 + 5
    x=17x = 17

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