Solve the expression: (13(1)/(12)+4(11)/(12))-6(9)/(40)

Add Fractions: Add the fractions with the same denominator. We have two fractions with the same denominator of 12, so we can add them directly. 13(1)/(12) + 4(11)/(12) = (13 + 4) + (1/12 + 11/12) = 17 + (12/12) = 17 + 1 = 18Convert to Improper Fraction: Convert the mixed number to an improper fraction. Now we need to convert 6(9)/(40) to an improper fraction to make the subtraction easier. 6(9)/(40) = (6 * 40 + 9)/40 = (240 + 9)/40 = 249/40Subtract Whole Number: Subtract the improper fraction from the whole number. Now we subtract the improper fraction from the whole number we obtained in Step 1. 18 - 249/40 To subtract, we need a common denominator. We can convert 18 to a fraction with a denominator of 40. 18 = 18 * (40/40) = (18 * 40)/40 = 720/40 Now we can subtract the two fractions. 720/40 - 249/40 = (720 - 249)/40 = 471/40Simplify Final Fraction: Simplify the fraction, if possible. The fraction 471/40 cannot be simplified further as 471 and 40 have no common factors other than 1. So, the final answer is 471/40.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve the expression:
(13(1)/(12)+4(11)/(12))-6(9)/(40)

Solve the expression: $\newline$ $(13\frac{1}{12}+4\frac{11}{12})-6\frac{9}{40}$

View step-by-step help

Home

Math Problems

Algebra 1

Multiplication with rational exponents

Full solution

Q. Solve the expression:

\newline

(13\frac{1}{12}+4\frac{11}{12})-6\frac{9}{40}

Add Fractions: Add the fractions with the same denominator. $\newline$ We have two fractions with the same denominator of $12$ , so we can add them directly. $\newline$ $\frac{13}{12} + \frac{4\times 11}{12} = (13 + 4) + \left(\frac{1}{12} + \frac{11}{12}\right)$ $\newline$ $= 17 + \left(\frac{12}{12}\right)$ $\newline$ $= 17 + 1$ $\newline$ $= 18$
Convert to Improper Fraction: Convert the mixed number to an improper fraction. $\newline$ Now we need to convert $6\left(\frac{9}{40}\right)$ to an improper fraction to make the subtraction easier. $\newline$ $6\left(\frac{9}{40}\right) = \left(6 \times 40 + 9\right)/40$ $\newline$ $= (240 + 9)/40$ $\newline$ $= 249/40$
Subtract Whole Number: Subtract the improper fraction from the whole number. $\newline$ Now we subtract the improper fraction from the whole number we obtained in Step $1$ . $\newline$ $18 - \frac{249}{40}$ $\newline$ To subtract, we need a common denominator. We can convert $18$ to a fraction with a denominator of $40$ . $\newline$ $18 = 18 \times \left(\frac{40}{40}\right) = \frac{18 \times 40}{40} = \frac{720}{40}$ $\newline$ Now we can subtract the two fractions. $\newline$ $\frac{720}{40} - \frac{249}{40} = \frac{720 - 249}{40}$ $\newline$ $= \frac{471}{40}$
Simplify Final Fraction: Simplify the fraction, if possible. $\newline$ The fraction $\frac{471}{40}$ cannot be simplified further as $471$ and $40$ have no common factors other than $1$ . $\newline$ So, the final answer is $\frac{471}{40}$ .