Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve the equation for all values of 
x.

|3x-5|=2x
Answer: 
x=

Solve the equation for all values of x x .\newline3x5=2x |3 x-5|=2 x \newlineAnswer: x= x=

Full solution

Q. Solve the equation for all values of x x .\newline3x5=2x |3 x-5|=2 x \newlineAnswer: x= x=
  1. Split Absolute Value: We have the equation 3x5=2x|3x - 5| = 2x. The absolute value equation can be split into two separate equations, one for the positive case and one for the negative case.\newlineFor the positive case, we simply remove the absolute value bars:\newline3x5=2x3x - 5 = 2x
  2. Positive Case Solution: Now, let's solve the equation 3x5=2x3x - 5 = 2x.
    Subtract 2x2x from both sides to isolate xx on one side:
    3x2x5=2x2x3x - 2x - 5 = 2x - 2x
    x5=0x - 5 = 0
  3. Positive Case Equation Solving: Add 55 to both sides to solve for xx: \newlinex5+5=0+5x - 5 + 5 = 0 + 5\newlinex=5x = 5\newlineThis is the solution for the positive case.
  4. Positive Case Final Solution: For the negative case, we consider the expression inside the absolute value to be negative: \newline3x5=2x-3x - 5 = 2x\newlineThis simplifies to:\newline3x+5=2x-3x + 5 = 2x
  5. Negative Case Consideration: Now, let's solve the equation 3x+5=2x-3x + 5 = 2x.\newlineAdd 3x3x to both sides to get all the xx terms on one side:\newline3x+3x+5=2x+3x-3x + 3x + 5 = 2x + 3x\newline5=5x5 = 5x
  6. Negative Case Equation Solving: Divide both sides by 55 to solve for xx:55=5x5\frac{5}{5} = \frac{5x}{5}1=x1 = xThis is the solution for the negative case.
  7. Negative Case Final Solution: We need to check if our solutions satisfy the original equation 3x5=2x|3x - 5| = 2x. Let's first check x=5x = 5:\newline3(5)5=2(5)|3(5) - 5| = 2(5)\newline155=10|15 - 5| = 10\newline10=10|10| = 10\newlineSince 1010 is positive, the absolute value of 1010 is indeed 1010. So, x=5x = 5 is a valid solution.
  8. Solution Checking for x=5x = 5: Now, let's check x=1x = 1:
    3(1)5=2(1)|3(1) - 5| = 2(1)
    35=2|3 - 5| = 2
    2=2|-2| = 2
    Since the absolute value of 2-2 is 22, x=1x = 1 is also a valid solution.

More problems from Evaluate absolute value expressions