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What is the midline equation of

{:[y=-9cos((pi)/(2)x-6)+8?],[y=]:}

What is the midline equation of\newliney=9cos(π2x6)+8?y= \begin{array}{l} y=-9 \cos \left(\frac{\pi}{2} x-6\right)+8 ? \\ y=\square \end{array}

Full solution

Q. What is the midline equation of\newliney=9cos(π2x6)+8?y= \begin{array}{l} y=-9 \cos \left(\frac{\pi}{2} x-6\right)+8 ? \\ y=\square \end{array}
  1. Midline of Trigonometric Function: The midline of a trigonometric function like y=Acos(BxC)+D y = A \cos(Bx - C) + D or y=Asin(BxC)+D y = A \sin(Bx - C) + D is the horizontal line y=D y = D , where D D is the vertical shift from the x-axis.
  2. Determining the Midline for the First Function: For the first function y=9cos(π2x6)+8 y = -9\cos\left(\frac{\pi}{2}x - 6\right) + 8 , the midline is given by the constant term outside the cosine function, which is +8 +8 .
  3. No Midline for the Second Function: For the second function, there is no explicit function given, so we cannot determine a midline for it.

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