Solve for z. z + 15/–2 = 2 z = _____

Move term to isolate z: Isolate the variable z on one side of the equation. To do this, we need to move the term 15/–2 to the other side of the equation by adding its opposite to both sides. z + 15/–2 + 15/2 = 2 + 15/2Simplify both sides: Simplify both sides of the equation. Since 15/–2 and 15/2 are opposites, they cancel each other out on the left side. On the right side, we need to find a common denominator to add 2 and 15/2. z = 2 + 15/2 z = (2 * 2)/2 + 15/2 z = 4/2 + 15/2 z = (4 + 15)/2 z = 19/2Convert to improper fraction: Convert the mixed number to an improper fraction if necessary. In this case, 19/2 is already an improper fraction, so no conversion is needed.

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Solve for $z$ . $\newline$ $z + \frac{15}{-2} = 2$ $\newline$ $z =$ _____

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Algebra 1

Solve multi-step linear equations

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Q. Solve for

z

\newline

z + \frac{15}{-2} = 2

\newline

z =

_____

Move term to isolate z: Isolate the variable $z$ on one side of the equation. $\newline$ To do this, we need to move the term $\frac{15}{-2}$ to the other side of the equation by adding its opposite to both sides. $\newline$ $z + \frac{15}{-2} + \frac{15}{2} = 2 + \frac{15}{2}$
Simplify both sides: Simplify both sides of the equation. $\newline$ Since $\frac{15}{-2}$ and $\frac{15}{2}$ are opposites, they cancel each other out on the left side. On the right side, we need to find a common denominator to add $2$ and $\frac{15}{2}$ . $\newline$ $z = 2 + \frac{15}{2}$ $\newline$ $z = \left(2 \times 2\right)/2 + \frac{15}{2}$ $\newline$ $z = \frac{4}{2} + \frac{15}{2}$ $\newline$ $z = \frac{4 + 15}{2}$ $\newline$ $z = \frac{19}{2}$
Convert to improper fraction: Convert the mixed number to an improper fraction if necessary. $\newline$ In this case, $\frac{19}{2}$ is already an improper fraction, so no conversion is needed.