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Solve for zz.\newline4z4|-4z| \leq 4\newlineWrite a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______

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Q. Solve for zz.\newline4z4|-4z| \leq 4\newlineWrite a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______
  1. Absolute Value Split: We have the inequality: \newline4z4|-4z| \leq 4 \newlineFirst, we solve for 4z|-4z|. \newline4z4|-4z| \leq 4 means that the absolute value of 4z-4z is less than or equal to 44.
  2. Solving First Inequality: The absolute value inequality 4z4|-4z| \leq 4 can be split into two separate inequalities because the absolute value of a number is the distance from zero, and it can be either positive or negative. So we have:\newline4z4-4z \leq 4 and 4z4-4z \geq -4
  3. Isolating z: Now we solve each inequality separately. Starting with the first one:\newline4z4-4z \leq 4\newlineTo isolate z, we divide both sides by 4-4. Remember that dividing by a negative number reverses the inequality sign.\newlinez1z \geq -1
  4. Solving Second Inequality: Now we solve the second inequality:\newline4z4-4z \geq -4\newlineAgain, we divide both sides by 4-4, and reverse the inequality sign.\newlinez1z \leq 1
  5. Combining Inequalities: Combining both inequalities, we get the compound inequality: \newline1z1-1 \leq z \leq 1\newlineThis is the solution to the original problem.

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