Solve for p.|p + 1| < 9Write a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.______
Q. Solve for p.∣p+1∣<9Write a compound inequality like 1<x<3 or like x<1 or x>3. Use integers, proper fractions, or improper fractions in simplest form.______
Given Inequality: We are given the inequality |p + 1| < 9. We need to consider two cases for the absolute value: one where the expression inside the absolute value is positive, and one where it is negative.
Case 1: Non-negative Expression: First, let's consider the case where the expression inside the absolute value is non-negative, which means p+1 is already positive. We can remove the absolute value signs:p + 1 < 9Now, we solve for p by subtracting 1 from both sides:p + 1 - 1 < 9 - 1p < 8
Case 2: Negative Expression: Next, we consider the case where the expression inside the absolute value is negative, which means we need to take the opposite of the expression inside to remove the absolute value signs:- (p + 1) < 9Now, we distribute the negative sign:-p - 1 < 9We solve for p by adding 1 to both sides and then multiplying by −1 to get p alone:-p - 1 + 1 < 9 + 1-p < 10Multiplying by −1 (and remembering to reverse the inequality sign):p > -10
Combining Cases: Combining the two cases, we get a compound inequality:-10 < p < 8This means p is greater than −10 and less than 8.
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