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Solve for zz.\newline2(z+6)=22(z+6)=2\newlinez=z=\newline

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Full solution

Q. Solve for zz.\newline2(z+6)=22(z+6)=2\newlinez=z=\newline
  1. Distribute and Simplify: Simplify the equation by distributing the 22 on the left side.\newline2(z+6)=22(z + 6) = 2\newline2z+2×6=22z + 2\times 6 = 2\newline2z+12=22z + 12 = 2
  2. Subtract to Isolate: Subtract 1212 from both sides to isolate the term with zz.\newline2z+12−12=2−122z + 12 - 12 = 2 - 12\newline2z=−102z = -10
  3. Divide to Solve: Divide both sides by 22 to solve for zz.\newline2z2=−102\frac{2z}{2} = \frac{-10}{2}\newlinez=−5z = -5

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