Solve for x. x^(2)-20 x+100=0 x=

Identify Equation Type: Identify the type of equation and look for patterns. The equation x^2 - 20x + 100 = 0 is a quadratic equation in the form of ax^2 + bx + c = 0. Notice that the equation can be factored because 100 is a perfect square and 20x is twice the product of the square root of 100 and x.Factor Quadratic Equation: Factor the quadratic equation. x^2 - 20x + 100 = (x - 10)(x - 10) = 0 This is because (x - 10)^2 = x^2 - 20x + 100.Solve for x: Solve for x by setting each factor equal to zero. Since (x - 10)(x - 10) = 0, we have x - 10 = 0.Find x Value: Find the value of x. x - 10 = 0 implies that x = 10.

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Solve for $x$ . $\newline$ $x^{2}-20x+100=0$ $\newline$ $x=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

x

\newline

x^{2}-20x+100=0

\newline

x=

Identify Equation Type: Identify the type of equation and look for patterns. $\newline$ The equation $x^2 - 20x + 100 = 0$ is a quadratic equation in the form of $ax^2 + bx + c = 0$ . $\newline$ Notice that the equation can be factored because $100$ is a perfect square and $20x$ is twice the product of the square root of $100$ and $x$ .
Factor Quadratic Equation: Factor the quadratic equation. $\newline$ $x^2 - 20x + 100 = (x - 10)(x - 10) = 0$ $\newline$ This is because $(x - 10)^2 = x^2 - 20x + 100$ .
Solve for x: Solve for x by setting each factor equal to zero. $\newline$ Since $(x - 10)(x - 10) = 0$ , we have $x - 10 = 0$ .
Find x Value: Find the value of x. $\newline$ $x - 10 = 0$ implies that $x = 10$ .