Solve for x. (x-1)/(8)-(x-3)/(10)=(7)/(40) Answer:

Find Common Denominator: Find a common denominator for the fractions to combine them. The common denominator for 8, 10, and 40 is 40. Multiply each term by 40/1 to clear the denominators. (40/1) * ((x-1)/8) - (40/1) * ((x-3)/10) = (40/1) * (7/40)Multiply by Common Denominator: Simplify each term. (40/8) * (x-1) - (40/10) * (x-3) = (40/40) * 7 5(x-1) - 4(x-3) = 7Simplify Terms: Distribute the coefficients inside the parentheses. 5x - 5 - 4x + 12 = 7Distribute Coefficients: Combine like terms. 5x - 4x - 5 + 12 = 7 x + 7 = 7Combine Like Terms: Isolate the variable x. x + 7 - 7 = 7 - 7 x = 0

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(x-1)/(8)-(x-3)/(10)=(7)/(40)
Answer:

Solve for $\mathrm{x}$ . $\newline$ $\frac{x-1}{8}-\frac{x-3}{10}=\frac{7}{40}$ $\newline$ Answer:

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Math Problems

Algebra 1

Solve multi-step linear equations

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Q. Solve for

\mathrm{x}

\newline

\frac{x-1}{8}-\frac{x-3}{10}=\frac{7}{40}

\newline

Answer:

Find Common Denominator: Find a common denominator for the fractions to combine them. $\newline$ The common denominator for $8$ , $10$ , and $40$ is $40$ . $\newline$ Multiply each term by $\frac{40}{1}$ to clear the denominators. $\newline$ $(\frac{40}{1}) \cdot (\frac{x-1}{8}) - (\frac{40}{1}) \cdot (\frac{x-3}{10}) = (\frac{40}{1}) \cdot (\frac{7}{40})$
Multiply by Common Denominator: Simplify each term. $\newline$ $(\frac{40}{8}) \times (x-1) - (\frac{40}{10}) \times (x-3) = (\frac{40}{40}) \times 7$ $\newline$ $5(x-1) - 4(x-3) = 7$
Simplify Terms: Distribute the coefficients inside the parentheses. $5x - 5 - 4x + 12 = 7$
Distribute Coefficients: Combine like terms. $\newline$ $5x - 4x - 5 + 12 = 7$ $\newline$ $x + 7 = 7$
Combine Like Terms: Isolate the variable $x$ . $\newline$ $x + 7 - 7 = 7 - 7$ $\newline$ $x = 0$