Solve for x in simplest form. 16=(5)/(8)(2x+32) Answer:

Isolate variable term: Isolate the term with the variable x. To do this, we need to get rid of the fraction (5/8) by multiplying both sides of the equation by its reciprocal, which is (8/5). (8/5) * 16 = (8/5) * (5/8)(2x + 32)Multiply by reciprocal: Perform the multiplication on the left side of the equation. (8/5) * 16 = 128/5Perform left side multiplication: Simplify the right side of the equation. (8/5) * (5/8)(2x + 32) simplifies to 2x + 32 because (8/5) and (5/8) cancel each other out. 128/5 = 2x + 32Simplify right side: Subtract 32 from both sides to isolate the term with x. 128/5 - 32 = 2x + 32 - 32Subtract 32: Convert 32 to a fraction with the same denominator as 128/5 to perform the subtraction. 32 = 32 * (5/5) = 160/5 128/5 - 160/5 = 2xConvert 32 to fraction: Perform the subtraction on the left side of the equation. 128/5 - 160/5 = -32/5 -32/5 = 2xPerform left side subtraction: Divide both sides by 2 to solve for x. (-32/5) / 2 = 2x / 2Divide by 2: Simplify the division to find the value of x. (-32/5) / 2 = -32/10 = -16/5 x = -16/5

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Solve for
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16=(5)/(8)(2x+32)
Answer:

Solve for $\mathrm{x}$ in simplest form. $\newline$ $16=\frac{5}{8}(2 x+32)$ $\newline$ Answer:

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Math Problems

Algebra 1

Solve multi-step linear equations

Full solution

Q. Solve for

\mathrm{x}

in simplest form.

\newline

16=\frac{5}{8}(2 x+32)

\newline

Answer:

Isolate variable term: Isolate the term with the variable $x$ . To do this, we need to get rid of the fraction $(\frac{5}{8})$ by multiplying both sides of the equation by its reciprocal, which is $(\frac{8}{5})$ . $(\frac{8}{5}) \times 16 = (\frac{8}{5}) \times (\frac{5}{8})(2x + 32)$
Multiply by reciprocal: Perform the multiplication on the left side of the equation. $\newline$ $(\frac{8}{5}) \times 16 = \frac{128}{5}$
Perform left side multiplication: Simplify the right side of the equation. $\newline$ $(\frac{8}{5}) \times (\frac{5}{8})(2x + 32)$ simplifies to $2x + 32$ because $(\frac{8}{5})$ and $(\frac{5}{8})$ cancel each other out. $\newline$ $\frac{128}{5} = 2x + 32$
Simplify right side: Subtract $32$ from both sides to isolate the term with $x$ . $\newline$ $\frac{128}{5} - 32 = 2x + 32 - 32$
Subtract $32$ : Convert $32$ to a fraction with the same denominator as $128/5$ to perform the subtraction. $\newline$ $32 = 32 \times (5/5) = 160/5$ $\newline$ $128/5 - 160/5 = 2x$
Convert $32$ to fraction: Perform the subtraction on the left side of the equation. $\newline$ $\frac{128}{5} - \frac{160}{5} = -\frac{32}{5}$ $\newline$ $-\frac{32}{5} = 2x$
Perform left side subtraction: Divide both sides by $2$ to solve for $x$ . $\left(-\frac{32}{5}\right) / 2 = \frac{2x}{2}$
Divide by $2$ : Simplify the division to find the value of $x$ . $\frac{-32}{5} / 2 = \frac{-32}{10} = \frac{-16}{5}$ $x = \frac{-16}{5}$