Solve for x. (3)/(10)+(3x+1)/(20)=-1 Answer:

Combine fractions with common denominator: Combine the fractions on the left side of the equation by finding a common denominator, which is 20. (3/10) * (2/2) + (3x+1)/20 = -1 (6/20) + (3x+1)/20 = -1Combine numerators over denominator: Combine the numerators over the common denominator. (6 + 3x + 1)/20 = -1 (3x + 7)/20 = -1Multiply both sides by 20: Multiply both sides by 20 to eliminate the denominator. 20 * ((3x + 7)/20) = 20 * (-1) 3x + 7 = -20Subtract 7 to isolate x: Subtract 7 from both sides to isolate the term with x. 3x + 7 - 7 = -20 - 7 3x = -27Divide both sides by 3: Divide both sides by 3 to solve for x. 3x / 3 = -27 / 3 x = -9

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(3)/(10)+(3x+1)/(20)=-1
Answer:

Solve for $\mathrm{x}$ . $\newline$ $\frac{3}{10}+\frac{3 x+1}{20}=-1$ $\newline$ Answer:

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

\mathrm{x}

\newline

\frac{3}{10}+\frac{3 x+1}{20}=-1

\newline

Answer:

Combine fractions with common denominator: Combine the fractions on the left side of the equation by finding a common denominator, which is $20$ . $\frac{3}{10} \times \frac{2}{2} + \frac{3x+1}{20} = -1$ $\frac{6}{20} + \frac{3x+1}{20} = -1$
Combine numerators over denominator: Combine the numerators over the common denominator. $\newline$ $(6 + 3x + 1)/20 = -1$ $\newline$ $(3x + 7)/20 = -1$
Multiply both sides by $20$ : Multiply both sides by $20$ to eliminate the denominator. $\newline$ $20 \times \left(\frac{3x + 7}{20}\right) = 20 \times (-1)$ $\newline$ $3x + 7 = -20$
Subtract $7$ to isolate $x$ : Subtract $7$ from both sides to isolate the term with $x$ . $3x + 7 - 7 = -20 - 7$ $3x = -27$
Divide both sides by $3$ : Divide both sides by $3$ to solve for $x$ . $\frac{3x}{3} = \frac{-27}{3}$ $x = -9$