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Solve for xx. \newline2x+4=162x+4 = 16 \newline x=x=\square

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Q. Solve for xx. \newline2x+4=162x+4 = 16 \newline x=x=\square
  1. Isolate x term: Isolate the term with the variable xx.\newlineTo do this, we need to get rid of the constant term on the same side as the variable. We can subtract 44 from both sides of the equation.\newline2x+44=1642x + 4 - 4 = 16 - 4\newline2x=122x = 12
  2. Solve for x: Solve for x.\newlineNow that we have isolated the term with xx, we can solve for xx by dividing both sides of the equation by the coefficient of xx, which is 22.\newline2x2=122\frac{2x}{2} = \frac{12}{2}\newlinex=6x = 6

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