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Let’s check out your problem:
Solve for
x
x
x
:
\newline
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
-2(8 x-1)+1=-5 x-(-4 x+6)
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
\newline
Answer:
x
=
x=
x
=
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
Solve for
x
x
x
:
\newline
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
-2(8 x-1)+1=-5 x-(-4 x+6)
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
\newline
Answer:
x
=
x=
x
=
Distribute and Simplify:
Distribute the
−
2
-2
−
2
into the parentheses on the left side of the equation.
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
-2(8x - 1) + 1 = -5x - (-4x + 6)
−
2
(
8
x
−
1
)
+
1
=
−
5
x
−
(
−
4
x
+
6
)
−
16
x
+
2
+
1
=
−
5
x
+
4
x
−
6
-16x + 2 + 1 = -5x + 4x - 6
−
16
x
+
2
+
1
=
−
5
x
+
4
x
−
6
Combine Like Terms:
Combine like terms on both sides of the equation.
\newline
−
16
x
+
3
=
−
x
−
6
-16x + 3 = -x - 6
−
16
x
+
3
=
−
x
−
6
Add and Subtract:
Add
x
x
x
to both sides to get all
x
x
x
terms on one side.
\newline
−
16
x
+
x
+
3
=
−
x
+
x
−
6
-16x + x + 3 = -x + x - 6
−
16
x
+
x
+
3
=
−
x
+
x
−
6
\newline
−
15
x
+
3
=
−
6
-15x + 3 = -6
−
15
x
+
3
=
−
6
Isolate x Term:
Subtract
3
3
3
from both sides to isolate the x term.
\newline
−
15
x
+
3
−
3
=
−
6
−
3
-15x + 3 - 3 = -6 - 3
−
15
x
+
3
−
3
=
−
6
−
3
\newline
−
15
x
=
−
9
-15x = -9
−
15
x
=
−
9
Divide to Solve:
Divide both sides by
−
15
-15
−
15
to solve for
x
x
x
.
\newline
−
15
x
/
−
15
=
−
9
/
−
15
-15x / -15 = -9 / -15
−
15
x
/
−
15
=
−
9/
−
15
\newline
x
=
9
/
15
x = 9 / 15
x
=
9/15
Simplify Fraction:
Simplify the
fraction
.
x
=
3
5
x = \frac{3}{5}
x
=
5
3
More problems from Solve linear equations: mixed review
Question
Solve for x.
\newline
(
3
4
)
x
=
12
(\frac{3}{4})x= 12
(
4
3
)
x
=
12
\newline
x
=
x =
x
=
______
Get tutor help
Posted 1 year ago
Question
Solve for x.
\newline
−
5
9
x
=
15
-\frac{5}{9}x= 15
−
9
5
x
=
15
\newline
x
=
x =
x
=
______
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
5
x
+
8
−
7
x
=
−
4
x
+
1
5x+8-7x=-4x+1
5
x
+
8
−
7
x
=
−
4
x
+
1
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
2
z
+
10
+
7
z
=
16
z
+
7
-2z+10+7z=16z+7
−
2
z
+
10
+
7
z
=
16
z
+
7
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 10 months ago
Question
How many solutions does the following equation have?
\newline
7
(
y
−
8
)
=
7
y
+
42
7(y-8)=7y+42
7
(
y
−
8
)
=
7
y
+
42
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
9
(
x
+
6
)
=
−
9
x
+
108
-9(x+6)=-9x+108
−
9
(
x
+
6
)
=
−
9
x
+
108
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
6
(
x
+
7
)
=
−
4
x
−
2
-6(x+7)=-4x-2
−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
4
x
−
7
+
10
x
=
−
7
+
6
x
-4x-7+10x=-7+6x
−
4
x
−
7
+
10
x
=
−
7
+
6
x
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
17
(
y
−
2
)
=
−
17
y
+
64
-17(y-2)=-17y+64
−
17
(
y
−
2
)
=
−
17
y
+
64
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
9z-6+7z=16z-6
9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Related topics
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Common Multiple
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