Solve for the exact value of x. log_(6)(9x)-log_(6)(4)=2

Use Quotient Rule: Step 1: Use the quotient rule for logarithms to combine the logs. log_6(9x/4) = 2Convert to Exponential Form: Step 2: Convert the logarithmic equation to its exponential form. 6^2 = 9x/4Solve for x: Step 3: Solve for x. 36 = 9x/4 144 = 9x x = 144/9 x = 16

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Solve for the exact value of
x.

log_(6)(9x)-log_(6)(4)=2

Solve for the exact value of $x$ . $\newline$ $\log_{6}(9x)-\log_{6}(4)=2$

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Math Problems

Calculus

Find derivatives of logarithmic functions

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Q. Solve for the exact value of

x

\newline

\log_{6}(9x)-\log_{6}(4)=2

Use Quotient Rule: Step $1$ : Use the quotient rule for logarithms to combine the logs. $\newline$ $\log_6\left(\frac{9x}{4}\right) = 2$
Convert to Exponential Form: Step $2$ : Convert the logarithmic equation to its exponential form. $\newline$ $6^2 = \frac{9x}{4}$
Solve for x: Step $3$ : Solve for x. $\newline$ $36 = \frac{9x}{4}$ $\newline$ $144 = 9x$ $\newline$ $x = \frac{144}{9}$ $\newline$ $x = 16$