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Let’s check out your problem:
Solve for
q
q
q
.
\newline
15
+
1
−
12
q
=
−
18
q
−
14
15 + 1 - 12q = -18q - 14
15
+
1
−
12
q
=
−
18
q
−
14
\newline
q
=
q =
q
=
__
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
Solve for
q
q
q
.
\newline
15
+
1
−
12
q
=
−
18
q
−
14
15 + 1 - 12q = -18q - 14
15
+
1
−
12
q
=
−
18
q
−
14
\newline
q
=
q =
q
=
__
Combine like terms:
Combine like terms on the left side of the equation.
\newline
15
+
1
−
12
q
=
−
18
q
−
14
15 + 1 - 12q = -18q - 14
15
+
1
−
12
q
=
−
18
q
−
14
\newline
(
15
+
1
)
−
12
q
=
−
18
q
−
14
(15 + 1) - 12q = -18q - 14
(
15
+
1
)
−
12
q
=
−
18
q
−
14
\newline
16
−
12
q
=
−
18
q
−
14
16 - 12q = -18q - 14
16
−
12
q
=
−
18
q
−
14
Add
q
q
q
terms:
Add
18
q
18q
18
q
to both sides to get all the
q
q
q
terms on one side.
\newline
16
−
12
q
+
18
q
=
−
18
q
−
14
+
18
q
16 - 12q + 18q = -18q - 14 + 18q
16
−
12
q
+
18
q
=
−
18
q
−
14
+
18
q
\newline
16
+
6
q
=
−
14
16 + 6q = -14
16
+
6
q
=
−
14
Subtract to isolate
q
q
q
:
Subtract
16
16
16
from both sides to isolate the
q
q
q
term.
\newline
16
+
6
q
−
16
=
−
14
−
16
16 + 6q - 16 = -14 - 16
16
+
6
q
−
16
=
−
14
−
16
\newline
6
q
=
−
30
6q = -30
6
q
=
−
30
Divide to solve for q:
Divide both sides by
6
6
6
to solve for
q
q
q
.
6
q
6
=
−
30
6
\frac{6q}{6} = \frac{-30}{6}
6
6
q
=
6
−
30
q
=
−
5
q = -5
q
=
−
5
More problems from Solve linear equations: mixed review
Question
Solve for x.
\newline
(
3
4
)
x
=
12
(\frac{3}{4})x= 12
(
4
3
)
x
=
12
\newline
x
=
x =
x
=
______
Get tutor help
Posted 1 year ago
Question
Solve for x.
\newline
−
5
9
x
=
15
-\frac{5}{9}x= 15
−
9
5
x
=
15
\newline
x
=
x =
x
=
______
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
5
x
+
8
−
7
x
=
−
4
x
+
1
5x+8-7x=-4x+1
5
x
+
8
−
7
x
=
−
4
x
+
1
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
2
z
+
10
+
7
z
=
16
z
+
7
-2z+10+7z=16z+7
−
2
z
+
10
+
7
z
=
16
z
+
7
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Posted 10 months ago
Question
How many solutions does the following equation have?
\newline
7
(
y
−
8
)
=
7
y
+
42
7(y-8)=7y+42
7
(
y
−
8
)
=
7
y
+
42
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
9
(
x
+
6
)
=
−
9
x
+
108
-9(x+6)=-9x+108
−
9
(
x
+
6
)
=
−
9
x
+
108
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
6
(
x
+
7
)
=
−
4
x
−
2
-6(x+7)=-4x-2
−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
4
x
−
7
+
10
x
=
−
7
+
6
x
-4x-7+10x=-7+6x
−
4
x
−
7
+
10
x
=
−
7
+
6
x
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
17
(
y
−
2
)
=
−
17
y
+
64
-17(y-2)=-17y+64
−
17
(
y
−
2
)
=
−
17
y
+
64
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
9z-6+7z=16z-6
9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
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