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Solve for pp.\newline5p10|-5p| \leq 10\newlineWrite a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______

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Q. Solve for pp.\newline5p10|-5p| \leq 10\newlineWrite a compound inequality like 1<x<31 < x < 3 or like x<1x < 1 or x>3x > 3. Use integers, proper fractions, or improper fractions in simplest form.\newline______
  1. Given Inequality: We have the inequality: \newline5p10|-5p| \leq 10\newlineFirst, we need to solve for 5p|-5p|. \newline5p10|-5p| \leq 10 means that the absolute value of 5p-5p is less than or equal to 1010.
  2. Splitting Inequality: The absolute value inequality 5p10|-5p| \leq 10 can be split into two separate inequalities because the absolute value of a number is the distance from zero, and it can be either positive or negative. So we have:\newline5p10-5p \leq 10 and 5p10-5p \geq -10
  3. Solving First Inequality: Now we solve each inequality for pp. Starting with the first inequality:\newline5p10-5p \leq 10\newlineTo isolate pp, we divide both sides by 5-5. Remember that dividing by a negative number reverses the inequality sign:\newlinep2p \geq -2
  4. Solving Second Inequality: Next, we solve the second inequality:\newline5p10-5p \geq -10\newlineAgain, we divide both sides by 5-5, and reverse the inequality sign:\newlinep2p \leq 2
  5. Combining Inequalities: Combining both inequalities, we get the compound inequality: \newline2p2-2 \leq p \leq 2\newlineThis is the solution to the given problem.

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