Solve for p. 14p + 20 + 7 = 16p - 3 p = ____

Simplify equation: First, let's simplify both sides of the equation by combining like terms. 14p + 20 + 7 = 16p - 3 14p + 27 = 16p - 3Combine terms: Next, we want to get all the terms with p on one side and the constants on the other side. To do this, we can subtract 14p from both sides of the equation. 14p + 27 - 14p = 16p - 3 - 14p 27 = 2p - 3Isolate variable term: Now, we will isolate the variable term by moving the constant on the right side to the left side. We do this by adding 3 to both sides of the equation. 27 + 3 = 2p - 3 + 3 30 = 2pSolve for p: Finally, we solve for p by dividing both sides of the equation by 2. 30 / 2 = 2p / 2 15 = p

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Solve for $p$ . $\newline$ $14p + 20 + 7 = 16p - 3$ $\newline$ p = ____

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

p

\newline

14p + 20 + 7 = 16p - 3

\newline

p = ____

Simplify equation: First, let's simplify both sides of the equation by combining like terms. $\newline$ $14p + 20 + 7 = 16p - 3$ $\newline$ $14p + 27 = 16p - 3$
Combine terms: Next, we want to get all the terms with $p$ on one side and the constants on the other side. To do this, we can subtract $14p$ from both sides of the equation. $14p + 27 - 14p = 16p - 3 - 14p$ $27 = 2p - 3$
Isolate variable term: Now, we will isolate the variable term by moving the constant on the right side to the left side. We do this by adding $3$ to both sides of the equation. $27 + 3 = 2p - 3 + 3$ $30 = 2p$
Solve for p: Finally, we solve for $p$ by dividing both sides of the equation by $2$ . $\frac{30}{2} = \frac{2p}{2}$ $15 = p$