Solve for n. 2n - 8 = 4n + 4 n = ____

Subtract n terms: First, we want to get all the n terms on one side of the equation and the constant terms on the other side. We can do this by subtracting 2n from both sides of the equation. 2n - 8 - 2n = 4n + 4 - 2n This simplifies to: -8 = 2n + 4Isolate n term: Next, we subtract 4 from both sides to isolate the term with n on one side. -8 - 4 = 2n + 4 - 4 This simplifies to: -12 = 2nDivide to solve n: Now, we divide both sides by 2 to solve for n. -12 / 2 = 2n / 2 This simplifies to: n = -6

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Solve for $n$ . $\newline$ $2n - 8 = 4n + 4$

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Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

n

\newline

2n - 8 = 4n + 4

Subtract n terms: First, we want to get all the $n$ terms on one side of the equation and the constant terms on the other side. We can do this by subtracting $2n$ from both sides of the equation. $2n - 8 - 2n = 4n + 4 - 2n$ This simplifies to: $-8 = 2n + 4$
Isolate $n$ term: Next, we subtract $4$ from both sides to isolate the term with $n$ on one side. $\newline$ $-8 - 4 = 2n + 4 - 4$ $\newline$ This simplifies to: $\newline$ $-12 = 2n$
Divide to solve $n$ : Now, we divide both sides by $2$ to solve for $n$ . $\newline$ $\frac{-12}{ 2} = \frac{2n}{2}$ This simplifies to: $\newline$ $n = -6$