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Solve for 
k.

(k)/(2)+(1)/(2)=3

Solve for k k .\newlinek2+12=3 \frac{k}{2}+\frac{1}{2}=3

Full solution

Q. Solve for k k .\newlinek2+12=3 \frac{k}{2}+\frac{1}{2}=3
  1. Combine fractions with common denominator: Combine the fractions on the left side of the equation by finding a common denominator, which is already 22.k2+12=3\frac{k}{2} + \frac{1}{2} = 3
  2. Add fractions: Add the fractions together. (k+1)/2=3(k + 1)/2 = 3
  3. Multiply to isolate kk: Multiply both sides of the equation by 22 to isolate kk.2×(k+12)=2×32 \times \left(\frac{k + 1}{2}\right) = 2 \times 3
  4. Simplify equation: Simplify both sides of the equation. k+1=6k + 1 = 6
  5. Subtract to solve for k: Subtract 11 from both sides to solve for kk. \newlinek+11=61k + 1 - 1 = 6 - 1
  6. Find value of k: Simplify the equation to find the value of kk.k=5k = 5

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