Solve for j. {:[(j)/(-2)+7=-12],[j=◻]:}

Isolate j term: First, we will focus on the equation (j)/(-2) + 7 = -12 and isolate the term containing j. (j)/(-2) + 7 = -12 Subtract 7 from both sides to isolate the term with j. (j)/(-2) + 7 - 7 = -12 - 7 (j)/(-2) = -19Multiply by -2: Now, we will multiply both sides by -2 to solve for j. (j)/(-2) * (-2) = -19 * (-2) j = 38Fill in the square: Since the second part of the system of equations is simply j=◻, we can fill in the square with the value we found for j. j = 38

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Solve for
j.

{:[(j)/(-2)+7=-12],[j=◻]:}

Solve for $j$ . $\newline$ $\begin{array}{l} \frac{j}{-2}+7=-12 \\ j=\square \end{array}$

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Algebra 1

Solve advanced linear inequalities

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Q. Solve for

j

\newline

\begin{array}{l} \frac{j}{-2}+7=-12 \\ j=\square \end{array}

Isolate j term: First, we will focus on the equation $\frac{j}{-2} + 7 = -12$ and isolate the term containing $j$ .
$\frac{j}{-2} + 7 = -12$
Subtract $7$ from both sides to isolate the term with $j$ .
$\frac{j}{-2} + 7 - 7 = -12 - 7$
$\frac{j}{-2} = -19$
Multiply by $-2$ : Now, we will multiply both sides by $-2$ to solve for $j$ . $\frac{j}{-2} \times (-2) = -19 \times (-2)$ $j = 38$
Fill in the square: Since the second part of the system of equations is simply $j=\square$ , we can fill in the square with the value we found for $j$ . $j = 38$