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Let’s check out your problem:
Factor the Polynomials below.
\newline
12
x
+
20
12x+20
12
x
+
20
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Math Problems
Algebra 1
Solve two-step linear inequalities
Full solution
Q.
Factor the Polynomials below.
\newline
12
x
+
20
12x+20
12
x
+
20
Identify GCF:
Identify the
greatest common factor
(
GCF
) of the terms in the polynomial
12
x
+
20
12x + 20
12
x
+
20
. The GCF of
12
12
12
and
20
20
20
is
4
4
4
.
Factor out GCF:
Factor out the GCF from the polynomial.
\newline
12
x
+
20
=
4
(
3
x
+
5
)
12x + 20 = 4(3x + 5)
12
x
+
20
=
4
(
3
x
+
5
)
More problems from Solve two-step linear inequalities
Question
What is the slope of the line?
\newline
y
+
2
=
−
2
(
x
−
3
)
y+2=-2(x-3)
y
+
2
=
−
2
(
x
−
3
)
\newline
Choose
1
1
1
answer:
\newline
(A)
−
1
-1
−
1
\newline
(B)
−
2
-2
−
2
\newline
(C)
1
1
1
\newline
(D)
−
1
2
-\frac{1}{2}
−
2
1
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Posted 1 year ago
Question
Solve for
t
t
t
.
\newline
4
(
t
+
1
4
)
=
3
4\left(t+\frac{1}{4}\right)=3
4
(
t
+
4
1
)
=
3
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Posted 1 year ago
Question
Solve for
k
k
k
.
\newline
k
2
+
1
2
=
3
\frac{k}{2}+\frac{1}{2}=3
2
k
+
2
1
=
3
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Posted 1 year ago
Question
Solve for
w
w
w
.
\newline
−
4
(
w
+
1
)
=
−
24
w
=
□
\begin{array}{l} -4(w+1)=-24 \\ w=\square \end{array}
−
4
(
w
+
1
)
=
−
24
w
=
□
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Posted 1 year ago
Question
Solve for
j
j
j
.
\newline
j
−
2
+
7
=
−
12
j
=
□
\begin{array}{l} \frac{j}{-2}+7=-12 \\ j=\square \end{array}
−
2
j
+
7
=
−
12
j
=
□
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Posted 1 year ago
Question
Let
g
(
x
)
=
x
3
−
16
x
g(x)=x^{3}-16 x
g
(
x
)
=
x
3
−
16
x
and let
c
c
c
be the number that satisfies the Mean Value Theorem for
g
g
g
on the interval
[
−
4
,
2
]
[-4,2]
[
−
4
,
2
]
.
\newline
What is
c
c
c
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
3
-3
−
3
\newline
(B)
−
2
-2
−
2
\newline
(C)
0
0
0
\newline
(D)
1
1
1
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Posted 1 year ago
Question
Evaluate
\newline
2
−
(
−
4
)
+
3
+
(
−
6
)
−
(
−
2
)
.
2-(-4)+3+(-6)-(-2) \text {. }
2
−
(
−
4
)
+
3
+
(
−
6
)
−
(
−
2
)
.
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Posted 1 year ago
Question
Evaluate
\newline
8
+
(
−
25
)
+
16
−
(
−
25
)
−
16
8+(-25)+16-(-25)-16
8
+
(
−
25
)
+
16
−
(
−
25
)
−
16
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Posted 1 year ago
Question
Solve for
v
v
v
.
\newline
13
≥
v
+
8
>
9
13 \geq v + 8 > 9
13
≥
v
+
8
>
9
\newline
Write your answer as a compound inequality with integers.
\newline
Choices:
\newline
(A)
5
≥
v
>
1
5 \geq v > 1
5
≥
v
>
1
\newline
(B)
v
>
5
v > 5
v
>
5
or
v
<
1
v < 1
v
<
1
\newline
(C)
5
>
v
>
1
5 > v > 1
5
>
v
>
1
\newline
(D)
v
≥
5
v \geq 5
v
≥
5
or
v
<
1
v < 1
v
<
1
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Posted 1 year ago
Question
You pick a card at random, put it back, and then pick another card at random.
\newline
4
4
4
\newline
5
5
5
\newline
6
6
6
\newline
7
7
7
\newline
What is the probability of picking a number greater than
5
5
5
and then picking a
4
4
4
?
\newline
Write your answer as a percentage.
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Posted 5 months ago
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