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Solve for jj.\newlinej−12.18=2.22j - 12.18 = 2.22\newlinej=j = _____

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Full solution

Q. Solve for jj.\newlinej−12.18=2.22j - 12.18 = 2.22\newlinej=j = _____
  1. Identify operation for isolation: Which operation should be used to isolate jj?\newlineIn j−12.18=2.22j - 12.18 = 2.22, we should add 12.1812.18 to both sides to isolate jj.\newlineAdd 12.1812.18
  2. Addition to isolate j: Perform the addition to find the value of j.\newlinej−12.18+12.18=2.22+12.18j - 12.18 + 12.18 = 2.22 + 12.18\newlinej=14.40j = 14.40

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