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Solve for jj.\newline4j+8=8+2j4j + 8 = -8 + 2j

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Q. Solve for jj.\newline4j+8=8+2j4j + 8 = -8 + 2j
  1. Subtract 2j2j: First, we want to get all the terms with jj on one side of the equation and the constant terms on the other side. We can do this by subtracting 2j2j from both sides of the equation.\newline4j+82j=8+2j2j4j + 8 - 2j = -8 + 2j - 2j
  2. Combine like terms: Now, we simplify both sides of the equation by combining like terms.\newline(4j2j)+8=8(4j - 2j) + 8 = -8\newline2j+8=82j + 8 = -8
  3. Isolate j term: Next, we want to isolate the term with j, so we subtract 88 from both sides of the equation to move the constant term to the other side.\newline2j+88=882j + 8 - 8 = -8 - 8
  4. Simplify both sides: Simplify both sides by combining like terms. 2j=162j = -16
  5. Solve for j: Finally, we solve for j by dividing both sides of the equation by 22.\newline2j2=162\frac{2j}{2} = \frac{-16}{2}\newlinej=8j = -8

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