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Solve for jj.\newline4j=23j+24j-4j = \frac{2}{3}j + 2 - 4j\newlinej=j = ____

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Q. Solve for jj.\newline4j=23j+24j-4j = \frac{2}{3}j + 2 - 4j\newlinej=j = ____
  1. Simplify the equation: First, let's simplify the equation by combining like terms on both sides.\newline4j=23j+24j-4j = \frac{2}{3}j + 2 - 4j\newlineCombine the 4j-4j terms on the right side.\newline4j=(23j4j)+2-4j = (\frac{2}{3}j - 4j) + 2
  2. Combine j terms: Now, we need to combine the j terms on the right side. To do this, we need a common denominator.\newline23j4j\frac{2}{3}j - 4j can be written as 23j(123)j\frac{2}{3}j - \left(\frac{12}{3}\right)j, since 4j4j is the same as (123)j\left(\frac{12}{3}\right)j.\newline4j=(23123)j+2-4j = \left(\frac{2}{3} - \frac{12}{3}\right)j + 2
  3. Subtract fractions: Next, subtract the fractions.\newline4j=(103)j+2-4j = \left(-\frac{10}{3}\right)j + 2\newlineNow we have a simplified equation.
  4. Isolate j term: Since 4j-4j is also on the left side, we can add (10/3)j(10/3)j to both sides to isolate the j term on the right.\newline4j+(10/3)j=2-4j + (10/3)j = 2\newlineTo combine the j terms on the left, we need a common denominator, which is 33.\newline(12/3)j+(10/3)j=2(-12/3)j + (10/3)j = 2
  5. Combine j terms: Combine the jj terms on the left side.(123+103)j=2\left(-\frac{12}{3} + \frac{10}{3}\right)j = 2 (23)j=2\left(-\frac{2}{3}\right)j = 2
  6. Solve for jj: To solve for jj, divide both sides by (23)(-\frac{2}{3}).j=2(23)j = \frac{2}{(-\frac{2}{3})}
  7. Multiply numbers: Dividing by a fraction is the same as multiplying by its reciprocal. j=2×(32)j = 2 \times \left(-\frac{3}{2}\right)
  8. Multiply numbers: Dividing by a fraction is the same as multiplying by its reciprocal. \newlinej=2×(32)j = 2 \times \left(-\frac{3}{2}\right)Now, multiply the numbers.\newlinej=3j = -3

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