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Solve for jj.\newline2(j+1)=102(j + 1) = 10

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Full solution

Q. Solve for jj.\newline2(j+1)=102(j + 1) = 10
  1. Distribute property simplification: Simplify 2(j+1)2(j + 1) by using the distributive property.\newline2(j+1)2(j + 1) \newline= 2(j)+2(1)2(j) + 2(1)\newline= 2j+22j + 2
  2. Equation setup: Set up the equation with the given value.\newline2j+2=102j + 2 = 10
  3. Isolate variable: Isolate 2j2j by subtracting 22 from both sides of the equation.\newline2j+2−2=10−22j + 2 - 2 = 10 - 2\newline2j=82j = 8
  4. Divide to solve: Divide both sides by 22 to solve for jj.2j2=82\frac{2j}{2} = \frac{8}{2}j=4j = 4

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