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Solve for jj.\newline2.37=j1.032.37 = j - 1.03\newlinej=j = _____

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Q. Solve for jj.\newline2.37=j1.032.37 = j - 1.03\newlinej=j = _____
  1. Identify Operation: Which operation should be used to isolate jj?\newlineIn 2.37=j1.032.37 = j - 1.03, we should add 1.031.03 to both sides to isolate jj.\newlineAdd 1.031.03 to both sides.
  2. Addition to Isolate jj: Perform the addition to find the value of jj.2.37+1.03=j2.37 + 1.03 = j3.40=j3.40 = j

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