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Solve for jj.\newline2+34j+12j=2j-2 + \frac{3}{4}j + \frac{1}{2}j = 2j\newlinej = ____

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Q. Solve for jj.\newline2+34j+12j=2j-2 + \frac{3}{4}j + \frac{1}{2}j = 2j\newlinej = ____
  1. Combine Like Terms: Combine like terms that contain the variable jj on the left side of the equation.2+(34+12)j=2j-2 + (\frac{3}{4} + \frac{1}{2})j = 2jTo combine the fractions, find a common denominator, which is 44.2+(34+24)j=2j-2 + (\frac{3}{4} + \frac{2}{4})j = 2j2+(54)j=2j-2 + (\frac{5}{4})j = 2j
  2. Find Common Denominator: Now, we want to get all the terms with jj on one side and the constant terms on the other side. Let's move the (5/4)j(5/4)j term to the right side by subtracting it from both sides.\newline2=2j(5/4)j-2 = 2j - (5/4)j\newlineTo subtract the fractions, they need to have the same denominator. The common denominator is 44, so we convert 2j2j to (8/4)j(8/4)j.\newline2=(8/4)j(5/4)j-2 = (8/4)j - (5/4)j
  3. Move Terms to Respective Sides: Subtract the jj terms on the right side.\newline2=(8454)j-2 = \left(\frac{8}{4} - \frac{5}{4}\right)j\newline2=(34)j-2 = \left(\frac{3}{4}\right)j
  4. Subtract Terms: To solve for jj, divide both sides by (3/4)(3/4), which is the same as multiplying by the reciprocal, 4/34/3.2×(4/3)=(3/4)j×(4/3)-2 \times (4/3) = (3/4)j \times (4/3)8/3=j-8/3 = j

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