Solve for d. d/3 − 1 = 1 d = _____

Isolate variable d: First, we want to isolate the variable d on one side of the equation. To do this, we can start by adding 1 to both sides of the equation to cancel out the -1 on the left side. d/3 − 1 + 1 = 1 + 1Add 1 to both sides: Now, we simplify both sides of the equation. d/3 = 2Simplify the equation: To solve for d, we need to get rid of the division by 3. We can do this by multiplying both sides of the equation by 3. (d/3) * 3 = 2 * 3Multiply by 3: After multiplying, we simplify the equation to find the value of d. d = 6

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Solve for $d$ . $\newline$ $\frac{d}{3} - 1 = 1$ $\newline$ $d =$ $\_\_\_\_\_$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

d

\newline

\frac{d}{3} - 1 = 1

\newline

d =

\_\_\_\_\_

Isolate variable d: First, we want to isolate the variable d on one side of the equation. To do this, we can start by adding $1$ to both sides of the equation to cancel out the $-1$ on the left side. $\newline$ $\frac{d}{3} - 1 + 1 = 1 + 1$
Add $1$ to both sides: Now, we simplify both sides of the equation. $\frac{d}{3} = 2$
Simplify the equation: To solve for $d$ , we need to get rid of the division by $3$ . We can do this by multiplying both sides of the equation by $3$ . $(\frac{d}{3}) \times 3 = 2 \times 3$
Multiply by $3$ : After multiplying, we simplify the equation to find the value of $d$ . $d = 6$