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Solve for dd.\newline3(d−19)+12=−33(d - 19) + 12 = -3\newlined=d = _____\_\_\_\_\_

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Full solution

Q. Solve for dd.\newline3(d−19)+12=−33(d - 19) + 12 = -3\newlined=d = _____\_\_\_\_\_
  1. Distribute and Simplify: First, distribute the 33 into the parentheses.3(d−19)+12=−33(d − 19) + 12 = −33d−57+12=−33d - 57 + 12 = −3
  2. Combine Like Terms: Next, combine like terms on the left side of the equation.\newline3d−57+12=−33d - 57 + 12 = -3\newline3d−45=−33d - 45 = -3
  3. Isolate Variable: Now, add 4545 to both sides to isolate the term with the variable dd. \newline3d−45+45=−3+453d - 45 + 45 = -3 + 45\newline3d=423d = 42
  4. Solve for d: Finally, divide both sides by 33 to solve for dd.3d3=423\frac{3d}{3} = \frac{42}{3}d=14d = 14

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