Solve for c. -4c - 2 = 10 - 8c c = ____

Combine like terms: First, we want to get all the terms with c on one side of the equation and the constant terms on the other side. We can do this by adding 8c to both sides of the equation. -4c - 2 + 8c = 10 - 8c + 8cSimplify equation: Now, we simplify both sides of the equation by combining like terms. (-4c + 8c) - 2 = 10 4c - 2 = 10Isolate c term: Next, we want to isolate the term with c, so we add 2 to both sides of the equation to move the constant term to the right side. 4c - 2 + 2 = 10 + 2 4c = 12Solve for c: Finally, we divide both sides of the equation by 4 to solve for c. 4c / 4 = 12 / 4 c = 3

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Solve for $c$ . $\newline$ $-4c - 2 = 10 - 8c$ $\newline$ $c =$ __

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Algebra 1

Solve linear equations with variables on both sides

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Q. Solve for

c

\newline

-4c - 2 = 10 - 8c

\newline

c =

Combine like terms: First, we want to get all the terms with $c$ on one side of the equation and the constant terms on the other side. We can do this by adding $8c$ to both sides of the equation. $\newline$ $-4c - 2 + 8c = 10 - 8c + 8c$
Simplify equation: Now, we simplify both sides of the equation by combining like terms. $\newline$ $(-4c + 8c) - 2 = 10$ $\newline$ $4c - 2 = 10$
Isolate c term: Next, we want to isolate the term with $c$ , so we add $2$ to both sides of the equation to move the constant term to the right side. $4c - 2 + 2 = 10 + 2$ $4c = 12$
Solve for c: Finally, we divide both sides of the equation by $4$ to solve for $c$ . $\newline$ $\frac{4c}{4} = \frac{12}{4}$ $\newline$ $c = 3$