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Solve for cc.\newline−4(c+11)=8-4(c + 11) = 8\newlinec=c = _____

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Full solution

Q. Solve for cc.\newline−4(c+11)=8-4(c + 11) = 8\newlinec=c = _____
  1. Distribute and Simplify: Distribute the −4-4 across the terms inside the parentheses.\newline-4(c + 11) = -4 \times c + -4 \times 11\(\newline= -4c - 44\)
  2. Set Equal and Isolate: Set the equation equal to 88 and isolate the term with cc. \newline−4c−44=8-4c - 44 = 8 \newlineAdd 4444 to both sides to isolate the term with cc. \newline−4c−44+44=8+44-4c - 44 + 44 = 8 + 44 \newline−4c=52-4c = 52
  3. Divide and Solve: Divide both sides by −4-4 to solve for cc.−4c−4=52−4\frac{-4c}{-4} = \frac{52}{-4}c=−13c = -13

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