Solve for c. 3 - 15c = -12c + 2 - 17 c = ____

Combine like terms: First, let's simplify the equation by combining like terms on the right side. 3 - 15c = -12c + 2 - 17 We combine the constants on the right side: 2 - 17 = -15. So the equation becomes: 3 - 15c = -12c - 15Move terms to one side: Next, we want to get all the terms with c on one side and the constants on the other side. Let's add 12c to both sides to move the c terms to the left side. 3 - 15c + 12c = -12c - 15 + 12c This simplifies to: 3 - 3c = -15Isolate the variable: Now, let's isolate the c term by moving the constant on the left side to the right side. We subtract 3 from both sides. 3 - 3 - 3c = -15 - 3 This simplifies to: -3c = -18Find the value of c: To find the value of c, we divide both sides by -3. -3c / -3 = -18 / -3 This gives us: c = 6

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Solve for $c$ . $\newline$ $3 - 15c = -12c + 2 - 17$ $\newline$ $c =$ __

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

c

\newline

3 - 15c = -12c + 2 - 17

\newline

c =

Combine like terms: First, let's simplify the equation by combining like terms on the right side. $\newline$ $3 - 15c = -12c + 2 - 17$ $\newline$ We combine the constants on the right side: $2 - 17 = -15$ . $\newline$ So the equation becomes: $\newline$ $3 - 15c = -12c - 15$
Move terms to one side: Next, we want to get all the terms with $c$ on one side and the constants on the other side. Let's add $12c$ to both sides to move the $c$ terms to the left side. $\newline$ $3 - 15c + 12c = -12c - 15 + 12c$ $\newline$ This simplifies to: $\newline$ $3 - 3c = -15$
Isolate the variable: Now, let's isolate the $c$ term by moving the constant on the left side to the right side. We subtract $3$ from both sides. $3 - 3 - 3c = -15 - 3$ This simplifies to: $-3c = -18$
Find the value of $c$ : To find the value of $c$ , we divide both sides by $-3$ . $\frac{-3c}{-3} = \frac{-18}{-3}$ This gives us: $c = 6$